Solving 3x3 Systems by Substitution (Part 1)

Solve 3x3 systems by substitution! Practice algebraic steps.

Use the steps to solve the following system:2x - 3y + z = 10y + 2z = 13z = 5 ( 7, 3, 5) Follow the steps in the table and match the step in the bank to solve the following system: x = -2y + 2z - 15 use equation#1 to solve for x= 2 (-2y + 2z - 15) + y - 5z = -21 substitute the expression for x into equation#2 -3y - z = 9 simplify previous step z = -3y - 9 solve for z= (-2y + 2z -15) - 4y +z =18 substitute the expression for x (from step 1) into equation#3 -6y + 3z = 33 simplify previous step -6y + 3 (-3y - 9) = 33 substitute z= into previous step y = -4 simplify previous step and solve for y= z = 3 substitute the y value into z= -3y - 9 and solve for z x = -2(-4) + 2(3) - 15 substitute the y and z values for step 1's equation x= x = -1 solve for x= ( -1, -4, 3) write as a solution Here is an extra video to help you Use the steps to solve the following system: ( -2, -4, 5)