Vertex to Standard Form

Change the quadratics from VERTEX FORM to STANDARD FORM and Identify the VERTEX. y=6x^2-48x+95 y=1 y=-5x^2+10x-1 (4,-1) (-4,6) (1,4) y=-1 y=4x^2+16x+8 (-6,-1) (-2,-8) (9,-2) y=x^2-4x+11 (2,7) (-1 (1 Match the following transformations on the parent function 𝒚 = 𝒙𝟐 (flip, stretched, compressed, left #, right #) y=-(x-2)^2 flip, right 2 y=(x+3)^2 - 1 left 3, down 1 y=3x^2 + 1 stretch, up 1 y=-2x^2 flip, stretch y=-x^2 - 5 flip, down 5 y=-(x+5)^2 flip, left 5 y=(x-1)^2 - 3 right 1, down 3 y=-x^2 - 2 flip, down 2 y=1 + 1 compress, up 1 State the vertex. (no spaces) y= (x+3)^2 (-3,0) y= -(x+1)^2 + 4 (-1,4) y= -.5(x-1)^2 - 6 (1,-6) y= x^2 (0,0) y= x^2 - 7 (0,-7) y= (x+4)^2 - 1 (-4,-1) Write the equation for the function 𝒚 = 𝒙𝟐 with the following transformations. (no spaces) Vertically reflected, shifted down 1 y=-x^2-1 Shifted up 5 y=x^2+5 Vertical stretch by a factor of 3, shifted right 5 and up 1 y=3(x-5)^2+1 Vertically reflected across the x-axis, shifted down 8 y=-x^2-8 Vertical reflection and vertical compression by a factor of 1 shifted left 3 and up 10 y=-1 Vertically stretched by a factor of 4, shifted left 3 and down 2 y=4(x+3)^2-2